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# Probability of surviving russian roulette

Aug 17,  · What's the probability of surviving (n) rounds of Russian roulette? It's a 6 shot revolver and you get to spin the cylinder on each round. (no missed shots and no misfires you die if . Mar 12,  · For some, the chances of survival are worse than the chances of surviving a round of Russian roulette. Advertisement - story continues below As we’ve seen since January, the SARS-CoV-2 virus’ oftentimes-deadly interaction with the human body makes it a much larger threat than even the worst influenza outbreaks of the century. Aug 29,  · In fact, with an 83% chance of survival in a game of Russian roulette, theoretically you could play indefinitely, though this is extremely unlikely.

## Russian Roulette (with additional rounds)

I'd go no further than 3 rounds, if I was playing with another Of these four spaces, only one of them is followed by a round. Rather than restricting the two rounds to be in adjacent chambers, let's calculate what would happen if they were placed in random locations. Cross your fingers and ask for a re-spin. Contact Us.

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Assume that we are playing a game of Russian roulette 6 chambers and that there is no shuffling after the shot is fired. I was just debating this with friends, and I wouldn't know what probability to use to prove it. I'm thinking binomial distribution or something like that. The person who goes second should have an advantage.

I've intentionally left fractions without reducing them as it's clearer where the numbers came from. So the two player game is fair without shuffling. Your best bet is actually to go last , because this will either make no difference or decrease the probability of shooting yourself. This reminds me of a similar interview question; you see your interviewer load two bullets into consecutive chambers of a gun, point at his head and pulls the trigger, but survives as it was an empty chamber.

He then gives you the gun to fire at your head, giving you the option to either spin the barrel before shooting or to just take the next shot. For 2 players and n chambers player 1 loses if the round is in the odd-numbered chamber. Sign up to join this community. The best answers are voted up and rise to the top. Home Questions Tags Users Unanswered. In Russian roulette, is it best to go first? Ask Question.

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When the spindle stops presumably in a random position , you pull the trigger. If the chamber was empty you live. If the round stopped in the firing position, you die. The probability of surviving is an, easy to calculate, and very unhealthy, You have a one in six chance that the live round stopped in the firing position. According to the internet so it has to be true , there is a variant of the Russian Roulette problem that is commonly asked as an interview question. It goes like this:.

You are tied to a chair. Now watch me as I put two bullets in the gun into adjacent chambers. I close the cylinder and spin it. I put the gun to your head and pull the trigger. Lucky you! Which would you prefer, that I spin the cylinder first or that I just pull the trigger? Oh, and missing from this interview question description, which I copied verbatim from the internet, is the assumption that you know that a revolver cylinder advances one position after each pull of the trigger.

The correct answer is that you should ask the interviewer to pull the trigger again , without spinning. If the cylinder is spun again, the second pull will be exactly the same risk as the first pull. There are two rounds, and six locations. There is a one in three chance that you will die. This probability does not change with any number of spins. There is a If the cylinder is not spun, the key to calculating the odds is the clue that the rounds are located in adjacent chambers. This means that there are two rounds next to each other, followed by four blank spaces.

We heard a click on the first pull, which means we are somewhere in the run of these four blank locations. Of these four spaces, only one of them is followed by a round. There is a one chance in four that we are at this bad location, and it means that there is a 3 in 4 chance that the chamber to come is empty. If we survive this second pull, and the devious torturer says he wants to pull the trigger a third time, well, at that point it makes no difference if the cylinder is spun, or the trigger is pulled one more time.

Let's change the problem. Rather than restricting the two rounds to be in adjacent chambers, let's calculate what would happen if they were placed in random locations. There are 6 choose 2 ways fifteen that two rounds can be placed into the cylinders. Without loss of generality, here they are:. We multiply these probabilities together. We next add the similar conditional probabilities for the six one-apart cases where two out of the four empty cells has a following empty chamber , and finally for the three opposite cases again where two out of the four empty cells has a following emoty chamber.

## Worlds safest roulette bet

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### Free Roulette

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